Which of the products will be major product in the reaction given below? Explain.
$\text{CH}_3\text{CH}=\text{CH}_2+\text{HI}\xrightarrow{ \ \ \ \ \ \ \ \ }\text{CH}_3\text{CH}_2\text{CH}_2\text{I}+\text{CH}_3\text{CHICH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{(A)} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{(B)}$
$\text{CH}_3\text{CH}=\text{CH}_2+\text{HI}\xrightarrow{ \ \ \ \ \ \ \ \ }\text{CH}_3\text{CH}_2\text{CH}_2\text{I}+\text{CH}_3\text{CHICH}_3\\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{(A)} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \text{(B)}$
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‘B’ will be the major product as per Markonikov rule. It is because of the generation of a reatively more stable secondary carbocation during the formation of the product (B).
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