MCQ
Angular momentum of electron in second shell of $Li^{+2}$ ion is
- A$6.62\times10^{-34}\, J\, sec$
- B$3.31\times10^{-27}\, erg.\, sec.$
- C$1.054\times10^{-27}\, erg.\, sec.$
- ✓$2.108\times10^{-27}\, erg.\, sec.$
$\therefore \quad \mathrm{mvr}=\frac{2 \times 6.62 \times 10^{-27}}{2 \times 3.14}$
$=2.108 \times 10^{-27} \text { erg. sec }$
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