MCQ
Xenon hexafluoride reacts with silica to form a xenon compound $X$. The oxidation state of $Xe$ in $X$ is :
- A$+2$
- B$+4$
- ✓$+6$
- D$0$
✓
Answer
Correct option: C.
$+6$
$\mathrm{SiO}_2+2 \mathrm{XeF}_6 \rightarrow 2 \mathrm{XeOF}_4+\mathrm{SiF}_4$
Oxidation state of $Xe$ in $(X)$ is $+ 6$
Oxidation state of $Xe$ in $(X)$ is $+ 6$
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