MCQ
Aniline with solid $KOH$ and $CS_2$ gives :
- AThiourea
- BPhenyl thio urea
- CPhenol
- ✓Diphenyl thio-urea
✓
Answer
Correct option: D.
Diphenyl thio-urea
d
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
$A\mathop {\xrightarrow{{{K_2}C{r_2}{O_7}}}}\limits_{{\text{dil}}{\text{. }}{H_2}S{O_4}} B\mathop {\xrightarrow{{C{H_3}MgI}}}\limits_{{H_2}O} $ $\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}} \\
|
\end{array}} \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,OH}
\end{array}$ The reactant $A$ is
→{\begin{array}{*{20}{c}}
{\,\,\,\,\,\,\,C{H_3}} \\
|
\end{array}} \\
{C{H_3} - C - C{H_3}} \\
| \\
{\,\,\,\,\,OH}
\end{array}$ The reactant $A$ is
$x,\, y$ and $z$ are respectively
→$MnO_4^ - \, + \,x{e^ - }\,\xrightarrow[{(Alkaline\,\,medium)}]{}MnO_4^{2 - }$
$MnO_4^ - \, + \,y{e^ - }\,\xrightarrow{{(Acidic\,\,medium)}}M{n^{2 + }}$
$MnO_4^ - \, + \,z{e^ - }\,\xrightarrow{{(Neutral\,\,medium)}}Mn{O_2}$
Benzaldehyde reacts with ammonia to form
If the rate of the reaction is equal to the rate constant, the order of the reaction is
The differential rate equation for the reaction $A+2 B$
$\longrightarrow$ product is :
→Product $(B)$ is :
→Which one of these group off elements is also called the halogen family?
Which compound is the most soluble in water?
Which is most reactive for $SN^1$
→$\mathrm{X}$ of enthanamine was subjected to reaction with $\mathrm{NaNO}_2 / \mathrm{HCl}$ followed by hydrolysis to liberate $\mathrm{N}_2$ and $\mathrm{HCl}$. The $\mathrm{HCl}$ generated was completely neutralised by $0.2$ moles of $\mathrm{NaOH} . \mathrm{X}$ is . . . . $g$.
→