MCQ
Any $p-$ orbital can accommodate up to:
- A$4$ electrons
- B$2$ electrons with parallel spins
- C$6$ electrons
- ✓$2$ electrons with opposite spins
✓
Answer
Correct option: D.
$2$ electrons with opposite spins
d
Any orbital can accommodate a maximum of $2$ electron with opposite spin so $p$ orbital can have $2$ electron with opposite spin.
Any orbital can accommodate a maximum of $2$ electron with opposite spin so $p$ orbital can have $2$ electron with opposite spin.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
In the following reaction:
→$HC \equiv CH\,\xrightarrow[{H{g^{2 + }}}]{{{H_2}S{O_4}}}\,'P'$
Product $'P'$ will not give
The electronegativity of $C,\,\,H,\,\,O,\,\,N$ and $S$ are $2.5$, $2.1$, $3.5$, $3.0$ and $2.5$ respectively. Which of the following bond is most polar
→Identify the incorrect order
Number of moles of methane required to produce $22 \mathrm{~g} \mathrm{CO}_{2(\mathrm{~g})}$ after combustion is $\mathrm{x} \times 10^{-2}$ moles. The value of $\mathrm{x}$ is
→The $I UPAC$ name of $\begin{matrix}
C{{H}_{3}}-CO-CH-C{{H}_{2}}-C{{H}_{2}}Cl \\
|\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\, \\
\end{matrix}$ is
→C{{H}_{3}}-CO-CH-C{{H}_{2}}-C{{H}_{2}}Cl \\
|\,\,\,\,\,\,\,\,\,\,\,\, \\
C{{H}_{3}}\,\,\,\,\,\,\, \\
\end{matrix}$ is
The electronic configuration of three elements $A,B$ and $C$ are given below. Stable form of $C$ may be represented by the formula
→$A : 1s^2\, 2s^2\, 2p^6$
$B : 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^3$
$C : 1s^2\, 2s^2\, 2p^6\, 3s^2\, 3p^5$
Which of the following solutions have the same concentration?
Which of the following solution becomes blue in colour when rod of copper had put in it?
The ascending acidity order of the following $\mathrm{H}$ atoms is $IMAGE$
→The enthalpy change $(\Delta H)$ for the reaction, $N_2 (g) + 3H_2 (g) \to 2NH_3(g)$ is $-92.38\, kJ$ at $298\, K$. The internal energy change $\Delta U$ at $298\, K$ is .............. $\mathrm{kJ}$
→