- A20g of NaOH in 200mL of solution.
- B0.5mol of KCl in 200mL of solution.
- C40g of NaOH in 100mL of solution.
- D20g of KOH in 200mL of solution.
Explanation:
$\text{Molarity}=\frac{\text{w}\times\text{1000}}{\text{M}\times\text{V(mL)}}$
$\text{Molarity}=\frac{\text{20}\times\text{1000}}{\text{40}\times\text{200}}=2.5\text{M}$
$\text{Molarity}=\frac{\text{0.5}\times\text{1000}}{\text{200}}=2.5\text{M}$
$\text{Molarity}=\frac{\text{40}\times\text{1000}}{\text{(40}\times\text{100)}}=10\text{M}$
$\text{Molarity}=\frac{\text{20}\times\text{1000}}{\text{(56}\times\text{200)}}=1.785\text{M}$
Thus (a) and (b) have the same molar concentration.
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