${H_2}C = CHC{H_2}Br\xrightarrow{{NaCN}}Y\xrightarrow[{2.\,{H_3}{O^ + }}]{\begin{subarray}{l} 1.{C_6}{H_5}MgBr\, \\ diethylether \end{subarray} }Z$
$\begin{array}{*{20}{c}} {C{H_3}\,\,\,} \\ {|\,\,\,\,\,\,\,\,} \\ {C{H_3} - C - CHC{H_3}} \\ {\,|\,\,\,\,\,\,\,\,\,\,|} \\ {\,\,H\,\,\,\,\,\,\,Br} \end{array}$ $\xrightarrow{{C{H_3}OH}}$