MCQ
Area of the triangle formed by the lines $y^2 -9xy + 18x^2 = 0$ and $y = 9$ , is ............ $\mathrm{sq. \,unit}$
- A$27$
- B$13.5$
- ✓$6.75$
- D$3.375$
$18 x^{2}-81 x+81=0$
$\Rightarrow \quad x=3, \frac{3}{2}$
So, we have three vertices $(0,0),(3,9)$
$\operatorname{and}\left(\frac{3}{2}, 9\right)$
Hence $\Delta=\frac{27}{4}$
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