MCQ
Armature current in dc motor will be maximum when
- AMotor has acquired maximum speed
- BMotor has acquired intermediate speed
- ✓Motor has just started moving
- DMotor is switched off
At starting ${E_b} = 0,$ so ${I_a}$will be maximum.
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$\left(\frac{1}{4 \pi \in_0}=9 \times 10^9 \mathrm{SI}\right.$ unit, mass of $\alpha$ particle $=$ $\left.6.72 \times 10^{-27} \mathrm{~kg}\right)$