MCQ
Arrange $S, P, As$ in order of increasing ionisation energy
- A$S < P < As$
- B$P < S < As$
- ✓$As < S < P$
- D$As < P < S$
✓
Answer
Correct option: C.
$As < S < P$
c
The increasing order of ionization enthalpy is $A s\,<\,S\,<\,P$.
The increasing order of ionization enthalpy is $A s\,<\,S\,<\,P$.
On moving from left to right in a period, the ionization energy increases with few irregularities where half filled and completely filled orbitals are involved. On moving down the group, the ionization energy decreases. Hence, the ionization enthalpy of $As$ is lowest. The ionization energy of $P$ is higher than the ionization energy of $S$ as in $P$, the electron is to be removed from half filled $3 p$ orbital whereas in case of $S$, the electron is to be removed from $3 p$ orbital containing $4$ electrons.
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