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Fractions (Including Problems) — MATHS STD 7 — Question

ICSE BoardEnglish MediumSTD 7MATHSFractions (Including Problems)4 Marks
Question
Arrange the given fraction in descending order by making numerator equal:
$\frac{1}{10}, \frac{6}{11}, \frac{8}{11} \text { and } \frac{3}{5}$
✓

Answer

$ \frac{1}{10}, \frac{6}{11}, \frac{8}{11} \text { and } \frac{3}{5} $
L.C.M. of numerators $1,6,8$ and $3=24$
$ \begin{aligned} & \therefore \frac{1}{10}=\frac{1 \times 24}{10 \times 24}=\frac{24}{240} \\ & \frac{6}{11}=\frac{6 \times 4}{11 \times 4}=\frac{24}{44} \\ & \frac{8}{11}=\frac{8 \times 3}{11 \times 3}=\frac{24}{33} \\ & \frac{3}{5}=\frac{3 \times 8}{5 \times 8}=\frac{24}{40} \end{aligned} $
It is clear from the above that
$ \begin{aligned} & \frac{24}{33}>\frac{24}{40}>\frac{24}{44}>\frac{24}{240} \\ & \text { or } \frac{8}{11}>\frac{3}{5}>\frac{6}{11}>\frac{1}{10} \end{aligned} $
Hence, $\frac{8}{11}, \frac{3}{5}, \frac{6}{11}, \frac{1}{10}$ are in descending order.

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