As shown in the figure, a current of $2\,A$ flowing in an equilateral triangle of side $4 \sqrt{3}\,cm$. The magnetic field at the centroid $O$ of the triangle is:
(Neglect the effect of earth's magnetic field.)
JEE MAIN 2023, Medium
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$d \tan 60^{\circ}=2 \sqrt{3}$
$d =2\,cm$
$B =3 \times \frac{\mu_0 i }{2 \pi d } \sin 60^{\circ}$
$=3 \times \frac{2 \times 10^{-7} \times 2}{2 \times 10^{-2}} \times \frac{\sqrt{3}}{2}$ $=3 \sqrt{3} \times 10^{-5}$
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