Assertion $(A):$ A spherical equipotential surface is not possible for a point charge.
Reason $(R):$ A spherical equipotential surface is possible inside a spherical capacitor.
AIIMS 2015, Medium
Download our app for free and get started
(d)
Download our appand get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Similar Questions
- 1View SolutionA parallel plate capacitor has two layers of dielectrics as shown in fig. This capacitor is connected across a battery, then the ratio of potential difference across the dielectric layers is
- 2In the circuit shown, the energy stored in $1\,\mu F$ capacitor is.....$\mu J$View Solution
- 3View SolutionThe electric potential inside a conducting sphere
- 4A capacitance of $2\ μF$ is required in an electrical circuit across a potential difference of $1.0\ kV$. A large number of $1\ μF$ capacitors are available which can withstand a potential difference of not more than $300\ V$. The minimum number of capacitors required to achieve this isView Solution
- 5View SolutionThe potential to which a conductor is raised, depends on
- 6View SolutionWhen a slab of dielectric material is introduced between the parallel plates of a capacitor which remains connected to a battery, then charge on plates relative to earlier charge
- 7A negative point charge placed at the point $A$ isView Solution
- 8View SolutionEquipotential surfaces are shown in figure. Then the electric field strength will be
- 9An electric charge $10^{-3}$ $\mu C$ is placed at the origin $(0, 0) $ of $X - Y$ co-ordinate system. Two points $A$ and $B$ are situated at $\left( {\sqrt 2 ,\sqrt 2 } \right)$ and $(2,0)$ respectively. The potential difference between the points $A$ and $B$ will be.......$V$View Solution
- 10In the circuit shown in figure, the ratio of charges on $5\ \mu F$ and $4\ \mu F$ capacitor is :View Solution
