Question
Assertion : In extreme position of a particle executing S.H.M., both velocity and acceleration are zero.
Reason $\quad:$ In S.H.M., acceleration always acts towards mean position.

Answer

(e) In simple harmonic motion the velocity is given by, $v=\omega \sqrt{a^2-y^2}$ at extreme position, $y=a$.$\therefore v=0$. But acceleration $A=-\omega^2 a$, which is maximum at extreme position.

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