$Assertion :$ Strain causes the stress in an elastic body.
$Reason :$ An elastic rubber is more plastic in nature.
AIIMS 2014, Medium
Download our app for free and get startedPlay store
Young'smodulus$(Y)=\frac{\text {stress}}{\text {strain}}$

If strain changes stress also changes since $Y$ is constant for a material.

Also, poisson's ratio $=\frac{\text { lateralstrain }}{\text { longitudinalstrain }}$

$\nu=0.5$ for rubber and is most elastic material.

So, both are correct but not reason of assertion.

art

Download our app
and get started for free

Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*

Similar Questions

  • 1
    A uniform plank of Young’s modulus $Y $ is moved over a smooth horizontal surface by a constant horizontal force $F.$ The area of cross section of the plank is $A.$ The compressive strain on the plank in the direction of the force is
    View Solution
  • 2
    When strain is produced in a body within elastic limit, its internal energy
    View Solution
  • 3
    The isothermal elasticity of a gas is equal to
    View Solution
  • 4
    As shown in the figure, forces of $10^5\,N$ each are applied in opposite directions, on the upper and lower faces of a cube of side $10\,cm$, shifting the upper face parallel to itself by $0.5\,cm$ . If the side of another cube of the same material is, $20\,cm$ then under similar conditions as above, the displacement will be......... $cm$
    View Solution
  • 5
    A copper wire of length $4.0m$ and area of cross-section $1.2\,c{m^2}$ is stretched with a force of $4.8 \times {10^3}$ $N.$ If Young’s modulus for copper is $1.2 \times {10^{11}}\,N/{m^2},$ the increase in the length of the wire will be
    View Solution
  • 6
    The Young's modulus of the material of a wire is $6 \times {10^{12}}\,N/{m^2}$ and there is no transverse strain in it, then its modulus of rigidity will be
    View Solution
  • 7
    In the given figure, two elastic rods $A$ & $B$ are rigidly joined to end supports. $A$ small mass $‘m’$ is moving with velocity $v$ between the rods. All collisions are assumed to be elastic & the surface is given to be frictionless. The time period of small mass $‘m’$ will be : [$A=$ area of cross section, $Y =$ Young’s modulus, $L=$ length of each rod ; here, an elastic rod may be treated as a spring of spring constant $\frac{{YA}}{L}$ ]
    View Solution
  • 8
    A uniform copper rod of length $50 \,cm$ and diameter $3.0 \,mm$ is kept on a frictionless horizontal surface at $20^{\circ} C$. The coefficient of linear expansion of copper is $2.0 \times 10^{-5} \,K ^{-1}$ and Young's modulus is $1.2 \times 10^{11} \,N / m ^2$. The copper rod is heated to $100^{\circ} C$, then the tension developed in the copper rod is .......... $\times 10^3 \,N$
    View Solution
  • 9
    A $100\,m$ long wire having cross-sectional area $6.25 \times 10^{-4}\,m ^2$ and Young's modulus is $10^{10}\,Nm ^{-2}$ is subjected to a load of $250\,N$, then the elongation in the wire will be :
    View Solution
  • 10
    A sample of a liquid has an initial volume of $1.5\,L$ . The volume is reduced by $0.2\,mL$ , when the pressure increases by $140\,kP$ . What is the bulk modulus of the liquid
    View Solution