Reason : $I_1 = I_2$ implies that the fields due to the current $I_1$ and $I_2$ will be balanced.
$\mathrm{B}_{1}=\frac{\theta}{2 \pi} \cdot \frac{\mu_{0} \mathrm{I}_{1}}{2 \mathrm{R}}$ and $\mathrm{B}_{2}=\frac{2 \pi-\theta}{2 \pi} \cdot \frac{\mu_{0} \mathrm{I}_{2}}{2 \mathrm{R}}$
Using $(1),$ we get $B_{1}=B_{2}$





Statement $I:$ Biot-Savart's law gives us the expression for the magnetic field strength of an infinitesimal current element (IdI) of a current carrying conductor only.
Statement $II :$ Biot-Savart's law is analogous to Coulomb's inverse square law of charge $q$, with the former being related to the field produced by a scalar source, Idl while the latter being produced by a vector source, $q$. In light of above statements choose the most appropriate answer from the options given below: