Question
Assign oxidation number to the underlined elements in the following species:
H2S2O7
H2S2O7
Then, we have
2(+1) + 2(x) + 7(-2) = 0
⇒ 2 + 2x - 14 = 0
⇒ 2x = 12
⇒ x = +6
Hence, the oxidation number of S is +6.
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