Question
Assign oxidation number to the underlined elements in the following species:

H2S2O7

Answer

$\begin{matrix} +1&\text{x}&-2\\\text{H}_2&\text{ S}_2&\ \text{ O}_7\end{matrix}$

Then, we have

2(+1) + 2(x) + 7(-2) = 0

⇒ 2 + 2x - 14 = 0

⇒ 2x = 12

⇒ x = +6

Hence, the oxidation number of S is +6.

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