Question
Assign oxidation number to the underlined elements in the following species:$\mathrm{NaHSO}_4$
✓
Answer
$\begin{matrix}\ \ +1&+1&\text{x}&-2\\\Rightarrow\ \text{Na}& \ \ \text{ H} &\text{S}&\ \text{ O}_4\end{matrix}$Then, we have
1(+1) + 1(+1) + 1(x) + 4(-2) = 0
⇒ 1 + 1 + x - 8 = 0
⇒ x = +6
Hence, the oxidation number of S is +6.
1(+1) + 1(+1) + 1(x) + 4(-2) = 0
⇒ 1 + 1 + x - 8 = 0
⇒ x = +6
Hence, the oxidation number of S is +6.
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