Question
Assign the position of the element having outer electronic configuration.
$(n-1) d^2 n s^2$ for $n=4$,
$(n-1) d^2 n s^2$ for $n=4$,
✓
Answer
Since $\mathrm{n}=4$, the element belongs to the $4^{\text {th }}$ period. It is a d-block element as d -orbital's are incompletely filled.
There are 2 electrons in the d-orbital.
Thus, the corresponding group of the element
$=$ Number of s-block groups + number of d-block groups
$=2+2$
$=4$
Therefore, it is a $4^{\text {th }}$ period and $4^{\text {th }}$ group element. Hence, the element is Titanium.
There are 2 electrons in the d-orbital.
Thus, the corresponding group of the element
$=$ Number of s-block groups + number of d-block groups
$=2+2$
$=4$
Therefore, it is a $4^{\text {th }}$ period and $4^{\text {th }}$ group element. Hence, the element is Titanium.
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