MCQ
Assume each reaction is carried out in an open container. For which reaction will $\Delta H = \Delta E$ ?
  • A
    $2CO _{(g)} + O_{2(g)} \rightarrow 2CO_{2(g)}$
  • $H_{2(g)} + Br_{2(g)} \rightarrow 2HBr_{(g)}$
  • C
    $C_{(s)} + 2H_2O_{(g)} \rightarrow 2H_{2(g)} + CO_{2(g)}$
  • D
    $PCl_{5(g)} \rightarrow PCl_{3(g)} + Cl_{2(g)}$

Answer

Correct option: B.
$H_{2(g)} + Br_{2(g)} \rightarrow 2HBr_{(g)}$
b
$\Delta H=\Delta E+\Delta n_{g} R T$

For $\mathrm{H}_{2(g)}+\mathrm{Br}_{2(g)} \rightarrow 2 \mathrm{HBr}_{(g)}$

$\Delta n_{g}=2-(1+1)=0 .$ i.e. $\Delta H=\Delta E$

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