$f=\frac{v}{4 L}$
As the water level increases $L$ length of air column decreases, hence frequency increases. But after some time when incoming water supply will be equal to the outgoing water. the length of air column will be constant. hence frequency will not change.
option $"B"$ is correct.

${y}_{1}={A}_{1} \sin {k}({x}-v {t}), {y}_{2}={A}_{2} \sin {k}\left({x}-{vt}+{x}_{0}\right) .$ Given amplitudes ${A}_{1}=12\, {mm}$ and ${A}_{2}=5\, {mm}$ ${x}_{0}=3.5\, {cm}$ and wave number ${k}=6.28\, {cm}^{-1}$. The amplitude of resulting wave will be $......\,{mm}$

$y\left( {x,t} \right) = 2\,\sin \,\left( {\frac{{2\pi }}{3}x} \right)\,\cos \,\left( {100\,\pi t} \right)$
where $x$ and $y$ are in $cm$ and $t$ is in $s$. Which of the following statements is correct ?
