At 298 ,K, the equilibrium constant is 2 10^ 15 for the reaction.… - Vidyadip

MCQ

At $298\,K$, the equilibrium constant is $2 \times 10^{15}$ for the reaction.

$Cu ( s )+2 Ag ^{+}( aq ) \rightleftharpoons Cu ^{2+}( aq )+2 Ag ( s )$

The equilibrium constant for the reaction.$\frac{1}{2} Cu ^{2+}( aq )+ Ag ( s ) \rightleftharpoons \frac{1}{2} Cu ( s )+ Ag ^{+}( aq )$ is $x \times 10^{-8}$. The value of $x$ is (Nearest Integer)

A
$3$
B
$0$
C
$1$
✓
$2$

✓

Answer

Correct option: D.

$2$

d
$K_{e q}^{\prime}=\frac{1}{\sqrt{K_{e q}}}=\frac{1}{\sqrt{2 \times 10^{15}}}=x \times 10^{-8}$

$\frac{1}{\sqrt{20}} \times \frac{1}{10^{7}}= x \times 10^{-8}$

$\frac{1}{\sqrt{20}} \times 10^{-7}= x \times 10^{-8}$

$\frac{10}{\sqrt{20}}= x$

$x=\frac{\sqrt{10}}{\sqrt{2}}=\sqrt{5}=2.236$

$\simeq 2.24$

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