MCQ
At $500K$, equilibrium constant, $K_c$ , for the following reaction is $5.\  \frac{1}{2}\text{H}_2\text{(g)}+\frac{1}{2}\text{I}_2\text{(g)}\rightleftharpoons\text{HI(g)}$ What would be the equilibrium constant $K_c$ for the reaction $2\text{HI}\text{(g)}\rightleftharpoons\text{H}_2\text{(g)}+\text{I}_2\text{(g)}$
  • $0.04$
  • B
    $0.4$
  • C
    $25$
  • D
    $2.5$

Answer

Correct option: A.
$0.04$
For the reaction,
$\frac{1}{2}\text{H}_2\text{(g)}+\frac{1}{2}\text{I}_2\text{(g)}\rightleftharpoons\text{HI(g)}\ ;\text{K}_\text{c}=5$
For $\text{H}_2\text{(g)}+\text{I}_2\text{(g)}\rightleftharpoons2\text{HI}\text{(g)}\ ;\text{K}_\text{c}=(5)^2=25$
For $2\text{HI}\text{(g)}\rightleftharpoons\text{H}_2\text{(g)}+\text{I}_2\text{(g)}\ ;\text{K}_\text{c}=\frac{1}{25}=0.04$

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