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6.2. Equilibrium - II (icon Equilibrium) — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry6.2. Equilibrium - II (icon Equilibrium)1 Mark
MCQ
At $90\,^oC$ pure water has $H_3O^+ = 10^{-6}\, mol\, litre^{-1}$. The value of $K_w$ at $90\,^oC$ is
  • A
    $10^{-6}$
  • ✓
    $10^{-12}$
  • C
    $10^{-14}$
  • D
    $10^{-8}$
✓

Answer

Correct option: B.
$10^{-12}$
b
$\mathrm{K}_{\mathrm{w}}=\left[\mathrm{H}^{+}\right]\left[\mathrm{OH}^{-}\right]$

and for pure $\mathrm{H}_{2} \mathrm{O},\left[\mathrm{H}^{+}\right]=\left[\mathrm{OH}^{-}\right]$

$\therefore \mathrm{K}_{\mathrm{w}}=\left[\mathrm{H}^{+}\right]^{2}=\left(10^{-6}\right)^{2}$

$=10^{-12}$

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