At equilibrium, the concentrations of N _2=3.0 10^ -3 M , O _2=4.2 10^ -3 M and NO =2.8 10^ -3 M in a sealed vessel at 800 K . What will be K _ c for the reaction N_2(g)+O_2(g) 2 NO(g)

At equilibrium, the concentrations of N _2=3.0 10^ -3 M , O _2=4.…

MCQ

At equilibrium, the concentrations of $N _2=3.0 \times 10^{-3}$ $M , O _2=4.2 \times 10^{-3} M$ and $NO =2.8 \times 10^{-3} M$ in a sealed vessel at 800 K . What will be $K _{ c }$ for the reaction
$N_2(g)+O_2(g) \rightleftharpoons 2 NO(g)$

A
1.622
B
6.22
✓
0.622
D
0.222

✓

Answer

Correct option: C.

0.622

(C) 0.622
For the reaction equilibrium constant, $K _{ c }$ can be written as
$K _{ C }=\frac{[ NO ]^2}{\left[N_2\right]\left[ O _2\right]}$
$K _{ C }=\frac{\left(2.8 \times 10^{-3} M \right)^2}{\left(3.0 \times 10^{-3} M \right)\left(4.2 \times 10^{-3} M \right)}$
$=0.622$

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