Question
अवकल समीकरण $\frac{{dy}}{{dx}} + \frac{y}{x} = {x^2}$ का हल है
अत: $I.F.$= ${e^{\int_{}^{} {\frac{1}{x}dx} }} = {e^{\log x}} = x$
अत: अभीष्ट हल $xy = \int_{}^{} {x.{x^2}dx + c} $
==> $xy = \frac{{{x^4}}}{4} + c$ ==> $4xy = {x^4} + 4c$
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