Question
Barium ions, $CN^{− }$ and $Co^{2+}$ form an ionic complex. If that complex is supposed to be $75\%$ ionised in water with vant Hoff factor $'i\ '$ equal to four, then the coordination number of $Co^{2+}$ in the complex can be.

Answer

Complex formed is $\ce{Bq_2​[CO(CN)_6​]}$ in which oxidation of $CO$ is $(2+)$ and $CN$ of $CO$ is six.

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