MCQ
Based on the following thermochemical equations

${H_2}O\left( g \right) + C\left( s \right) \to CO\left( g \right) + {H_2}\left( g \right);\Delta H = 131\,kJ$

$CO\left( g \right) + \frac{1}{2}{O_2}\left( s \right) \to C{O_2}\left( g \right);\Delta H =  - 282\,kJ$

${H_2}\left( g \right) + \frac{1}{2}{O_2}\left( s \right) \to {H_2}O\left( g \right);\Delta H =  - 242\,kJ$

$C(s) + O_2(g) \to CO_2(g); \Delta H = X\,kJ$

The value of $X$ will be......$kJ$

  • $-393$
  • B
    $-655$
  • C
    $+393$
  • D
    $+655$

Answer

Correct option: A.
$-393$
a
$\mathrm{H}_{2} \mathrm{O}(\mathrm{g})+\mathrm{C}(\mathrm{s}) \rightarrow \mathrm{CO}(\mathrm{g})+\mathrm{H}_{2}(\mathrm{g})$ $\Delta {\text{H}} = 131\,{\text{KJ}}....{\text{(1)}}$

${\text{CO}}({\text{g}}) + \frac{1}{2}{{\text{O}}_2}({\text{g}}) \to {\text{C}}{{\text{O}}_2}({\text{g}})\,\,\Delta {\text{H}} =  - 282\,{\text{KJ}}.....{\text{(2)}}$

${{\text{H}}_2}({\text{g}}) + \frac{1}{2}{{\text{O}}_2}({\text{g}}) \to {{\text{H}}_2}{\text{O}}\,\,\Delta {\text{H = }} - 242\,{\text{KJ}}....(3)$

${C_{(s)}} + {{\text{O}}_2}({\text{g}}) \to {\text{C}}{{\text{O}}_2}\,\Delta {\text{H}} = {\text{x}}\,{\text{KJ}}....{\text{(4)}}$

$(1) + (2) + (3) = 4$

$131 - 282 - 242 = {\text{x}}$

$x =  - 393\,{\text{kJ}}$

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