MCQ
Based on $VSEPR$ theory, the number of $90$ degree $\mathrm{F}-\mathrm{Br}-\mathrm{F}$ angles in $\mathrm{BrF}_5$ is
  • A
    $5$
  • $0$
  • C
    $3$
  • D
    $7$

Answer

Correct option: B.
$0$
b
All four planar bonds $(\mathrm{F}-\mathrm{Br}-\mathrm{F})$ will reduce from $90^{\circ}$ to $84.8^{\circ}$ after $\ell \mathrm{p}-$ $bp$ repulsion.

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