- AExhibiting amphoteric nature in their oxides
- ✓Forming polymeric hydrides
- CExhibiting maximum covalency in compounds
- DForming covalent halides
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$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}\left(\mathrm{NO}_2\right)-\mathrm{COOH} $
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CHBr}-\mathrm{CH}_2-\mathrm{CH}_3 $
$ \mathrm{CH}_3-\mathrm{CH}(\mathrm{I})-\mathrm{CH}_2-\mathrm{NO}_2 $
$ \mathrm{CH}_3-\mathrm{CH}_2-\mathrm{CH}(\mathrm{OH})-\mathrm{CH}_2 \mathrm{OH} $
$ \mathrm{CH}_3-\mathrm{CH}-\mathrm{CH}(\mathrm{I})-\mathrm{C}_2 \mathrm{H}_5 $
Assertion $A:$ $5 f$ electrons can participate in bonding to a far greater extent than $4 f$ electrons
Reason $R:$ $5 f$ orbitals are not as buried as $4 f$ orbitals
In the light of the above statements, choose the correct answer from the options given below