MCQ
$BeCl _{2}$ reacts with $LiAlH _{4}$ to give ....
- A$Be + Li \left[ AlCl _{4}\right]+ H _{2}$
- B$Be + AlH _{3}+ LiCl + HCl$
- ✓$BeH _{2}+ LiCl + AlCl _{3}$
- D$BeH _{2}+ Li \left[ AlCl _{4}\right]$
This is the method to prepare $BeH _{2}$
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$(i) C_2H_5OH \longrightarrow CH_3CHO$
$(ii) C_2H_5OH \longrightarrow C_2H_5ONa$
$I . C H_{3}^{+}$ $II.$ $H_{3} O ^{+}$ $III.$ $N H_{3}$ $I V\,\, C H_{3}^{-}$
$3 \mathrm{PbCl}_2+2\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4 \rightarrow \mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2+6 \mathrm{NH}_4 \mathrm{Cl}$
If $72 \mathrm{mmol}$ of $\mathrm{PbCl}_2$ is mixed with $50 \mathrm{mmol}$ of$\left(\mathrm{NH}_4\right)_3 \mathrm{PO}_4$, then amount of $\mathrm{Pb}_3\left(\mathrm{PO}_4\right)_2$ formed is......... mmol. (nearest integer)
$PCl_{5(g)} \rightleftharpoons PCl_{3(g)} + Cl_{2(g)}$
which of the following conditions are correct ?