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9. Hydricarbon — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry9. Hydricarbon1 Mark
MCQ
$\begin{array}{*{20}{c}}
  {C{H_3} - C = CH - C{H_3}} \\ 
  {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {C{H_3}\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{KMn{O_4}/\Delta }]{{NaI{O_4}}}$ Product will be
  • A
    $CH_3-COOH + CH_3-CH_2-COOH$
  • B
    $CH_3-CHO + CH_3-CH_2-COOH$
  • C
    $CH_3-CHO +$ $\begin{array}{*{20}{c}}
      {C{H_3} - C - C{H_3}} \\ 
      {||\,} \\ 
      {O\,} 
    \end{array}$
  • ✓
    $CH_3-COOH +$ $\begin{array}{*{20}{c}}
      {C{H_3} - C - C{H_3}} \\ 
      {||\,} \\ 
      {O\,} 
    \end{array}$
✓

Answer

Correct option: D.
$CH_3-COOH +$ $\begin{array}{*{20}{c}}
  {C{H_3} - C - C{H_3}} \\ 
  {||\,} \\ 
  {O\,} 
\end{array}$
d

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