MCQ
$\begin{array}{*{20}{c}}
  {C{H_3} - CH - C - O - C{H_3} + 2C{H_3}MgBr\, \to \,A} \\ 
  {||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
  {O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} 
\end{array}$ 

$\xrightarrow[\Delta ]{{{H^ \oplus }}}\,B$

The product $"B"$ is

  • $\begin{array}{*{20}{c}}
    {C{H_3} - C = CH - C{H_3}}\\
    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
    {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
    \end{array}$
  • B
    $\begin{array}{*{20}{c}}
    {C{H_3} - CH - CH = C{H_2}}\\
    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
    {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,}
    \end{array}$
  • C
    $\begin{array}{*{20}{c}}
      {OH\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {C{H_3} - C - C{H_2} - C{H_3}} \\ 
      {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\ 
      {\,C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,} 
    \end{array}$
  • D
    $\begin{array}{*{20}{c}}
    {\begin{array}{*{20}{c}}
    {\,\,\,\,\,\,\,\,\,C{H_3}}\\
    |
    \end{array}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
    {C{H_3} - C - C{H_2} - OH}\\
    {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
    {C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,}
    \end{array}$

Answer

Correct option: A.
$\begin{array}{*{20}{c}}
{C{H_3} - C = CH - C{H_3}}\\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$
a

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