{{{(C{H_3})}_2}C.C{H_2}.CO.C{H_3}} \\
{\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,\,\,N{H_2}\,\,\,\,\,\,\,}
\end{array}$ is
- ADiacetone
- BAcetonamine
- ✓Diacetonamine
- DAminoacetone
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$Zn ^{2+}+2 e ^{-} \rightarrow Zn ; E ^{\circ}=-0.760 \,V$
$Ag _{2} O + H _{2} O +2 e ^{-} \rightarrow 2 Ag +2 OH ^{-} ; E ^{\circ}=0.344 \,V$
If $F$ is $96,500 C mol ^{-1}$ $\Delta G ^{\circ}$ of the cell will be $....$ (In $kJ mol ^{-1}$)
$\begin{array}{*{20}{c}}
{O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C \equiv CH\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,O\,\,\,} \\
{\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,||\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{Cl - C - C{H_2} - C - C{H_2} - C{H_2} - C - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C{H_2}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{C \equiv N\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow[{BaS{O_4}}]{{{H_2}/Pd}}\,'X'$