MCQ
Benzamide and benzyl amine can be distinguished by
- Acold dil. $NaOH$
- ✓cold dil. $HCl$
- Cboth $a$ and $b$
- D$NaNO_2$, $HCl$, $0\,^oC$, then $\beta - $ naphthol
✓
Answer
Correct option: B.
cold dil. $HCl$
b
Cold dil. $NaOH$ does not attack to either of the compound, while cold dil. $HCl$ reacts only with benzyl amine $C_6H_5CH_2NH_2$.
Cold dil. $NaOH$ does not attack to either of the compound, while cold dil. $HCl$ reacts only with benzyl amine $C_6H_5CH_2NH_2$.
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