MCQ
Benzamide and benzyl amine can be distinguished by
  • A
    cold dil. $NaOH$
  • cold dil. $HCl$
  • C
    both $a$ and $b$
  • D
    $NaNO_2$, $HCl$, $0\,^oC$, then $\beta  - $ naphthol

Answer

Correct option: B.
cold dil. $HCl$
b
Cold dil. $NaOH$ does not attack to either of the compound, while cold dil. $HCl$ reacts only with benzyl amine $C_6H_5CH_2NH_2$.

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