Benzene burns according to the following equation at 300 , K (R =… - Vidyadip

MCQ

Benzene burns according to the following equation at $300\, K$ $(R = 8.314\, J\, mole^{-1}K^{-1}), 2C_6H_6(l) + 15 O_2 (g) \to 12 CO_2 (g) + 6H_2O(l)$, $\Delta H^o = -6542\, kJ/mol$ What is the $\Delta E^o$ for the combustion of $1.5\, mol$ of benzene.....$kJ$

A
$-3271$
B
$-9813$
✓
$-9807.37$
D
$4912.11$

✓

Answer

Correct option: C.

$-9807.37$

c
$\Delta \mathrm{H}+\Delta \mathrm{E}+\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}$

$\therefore \Delta \mathrm{E}=\Delta \mathrm{H}-\Delta \mathrm{n}_{\mathrm{g}} \mathrm{RT}$

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