MCQ
$Benzene$ $\xrightarrow[{{H_2}S{O_4}}]{{HN{O_3}}}\left( A \right)\xrightarrow[{FeC{l_3}}]{{C{l_2}}}\left( B \right)$
The major product $(B)$ is
- ✓

- B

- C

- D

The major product $(B)$ is






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$Al_2Cl_6$ $-$ $Al_2(CH_3)_6$ $-$ $AlF_3$ $-$ Dimer of $BeCl_2$ $-$ Dimer of $BeH_2$
(Note : $C$ for complete octet and $IC$ for incomplete octet.)