Question
Between the first and fifth nodes is 40 cm then find wavelength of wave?
✓
Answer
We know that distance between two consecutive nodes is $\frac{\lambda}{2}$.
So first and fifth between distance $\frac{4 \times \lambda}{2}$ Means it is equal to $2 \lambda$.
$\therefore \quad 2 \lambda=40 \quad \therefore \lambda=\frac{40}{2}=20 cm$
So first and fifth between distance $\frac{4 \times \lambda}{2}$ Means it is equal to $2 \lambda$.
$\therefore \quad 2 \lambda=40 \quad \therefore \lambda=\frac{40}{2}=20 cm$
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