$\Big(\frac{-3}{8}\Big)+\Big(\frac{19}{24}\Big)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$ Solution: $\Big(\frac{-3}{8}\Big)+(\dots)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$ $(\dots)=\frac{5}{12}+\frac{3}{8}$ LCM of 12 and 8 is 24 $(\dots)=\frac{10+9}{24}$ $(\dots)=\frac{19}{24}$
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