Question
$\Big(\frac{-3}{8}\Big)+(\dots)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$

Answer

$\Big(\frac{-3}{8}\Big)+\Big(\frac{19}{24}\Big)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$
Solution:
$\Big(\frac{-3}{8}\Big)+(\dots)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$
$(\dots)=\frac{5}{12}+\frac{3}{8}$
LCM of 12 and 8 is 24
$(\dots)=​​\frac{10+9}{24}$
$(\dots)=​​\frac{19}{24}$

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