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MATHS BLANKS [1 Marks Each]

Rational Numbers · Gujarat Board (GSEB) STD 7 (GSEB - English Medium). 14 questions.

Questions

BLANKS [1 Marks Each]

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14 questions · timed · auto-graded

Question 11 Mark
$\frac{9}{8}\div(\dots)=\frac{-3}{2}$
Answer
$\frac{9}{8}\div\Big(\frac{-3}{4}\Big)=\frac{-3}{2}$
Solution:
$\frac{9}{8}\div(\dots?\dots)=\frac{-3}{2}$
$\frac{9}{8}\div(\dots?\dots)=\frac{(-3)}{2}$
$(\dots?\dots)=\frac{9}{8}\times\frac{2}{(-3)}$
$(\dots?\dots)=\frac{-3}{4}$
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Question 21 Mark
$(\dots)\div\Big(\frac{-7}{5}\Big)=\frac{10}{19}$
Answer
$\Big(\frac{-14}{19}\Big)\div\Big(\frac{-7}{5}\Big)=\frac{10}{19}$
Solution:
$(\dots?\dots)\div\Big(\frac{-7}{5}\Big)=\frac{10}{19}$
$(\dots?\dots)=\frac{10}{19}\times\frac{-7}{5}$
$(\dots?\dots)=\frac{-14}{19}$
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Question 61 Mark
$\Big(\frac{-65}{14}\Big)+(\dots)=2\frac{1}{2}$
Answer
$\Big(\frac{-65}{14}\Big)+\Big(\frac{14}{15}\Big)+2\frac{1}{2}$
Solution:
$\Big(\frac{-65}{14}\Big)+(\dots)=2\frac{1}{2}$
$=\frac{-65}{14}+\frac{5}{2}$
$=\frac{-65}{14}\times\frac{2}{5}$
$=\frac{-13}{7}$
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Question 71 Mark
$\Big(\frac{-3}{8}\Big)+(\dots)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$
Answer
$\Big(\frac{-3}{8}\Big)+\Big(\frac{19}{24}\Big)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$
Solution:
$\Big(\frac{-3}{8}\Big)+(\dots)=\frac{5}{12}-\Big(\frac{-3}{8}\Big)$
$(\dots)=\frac{5}{12}+\frac{3}{8}$
LCM of 12 and 8 is 24
$(\dots)=​​\frac{10+9}{24}$
$(\dots)=​​\frac{19}{24}$
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Question 81 Mark
Multiplicative inverse of $-1\frac{3}{4}$ is ....
Answer
Multiplicative inverse of $-1\frac{3}{4},$ i.e.,
Solution:
Multiplicative inverse of $-1\frac{3}{4},$ i.e.,
$\frac{-7}{4}\text{ is }\frac{-4}{7}$
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Question 91 Mark
Fill in the blank with the correct symbol out of >, = and<.
$\frac{-8}{9}\ ......\ \frac{-9}{10}$
Answer
self
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Question 101 Mark
Fill in the blank with the correct symbol out of >, = and<.
$\frac{5}{-13}\ ......\ \frac{-35}{91}$
Answer
self
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Question 111 Mark
Fill in the blank with the correct symbol out of >, = and<.
$\frac{-3}{7}\ ......\ \frac{6}{-13}$
Answer
$\frac{-3}{7}>\frac{6}{-13}$

Solution:

$\frac{6}{-13}=\frac{6\times(-1)}{-13\times(-1)}=\frac{-6}{13}$

(Making denominator positive)

LCM of 7 and 13 = 91

$\therefore\frac{-3}{7}=\frac{-3\times13}{7\times13}=\frac{-39}{91}$

$\frac{-6}{13}=\frac{-6\times7}{13\times7}=\frac{-42}{91}$

It is clear that $\frac{-39}{91}>\frac{-42}{91}$

$\therefore\frac{-3}{7}>\frac{6}{-13}$

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Question 121 Mark
Fill in the blank with the correct symbol out of >, = and<.
$\frac{-2}{3}\ ......\ \frac{5}{-8}$
Answer
$\frac{-2}{3}<\frac{5}{-8}$

Solution:

$\frac{5}{-8}=\frac{5\times(-1)}{-8\times(-1)}=\frac{-5}{8}$

LCM of 3 and 8 = 24

$\therefore\frac{-2}{3}=\frac{-2\times8}{3\times8)}=\frac{-16}{24}$

$\frac{-5}{8}=\frac{-5\times3}{8\times3}=\frac{-15}{24}$

It is clear that $\frac{-16}{24}=\frac{-15}{24}$

$\therefore\frac{-2}{3}<\frac{5}{-8}$

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Question 141 Mark
Fill in the blank with the correct symbol out of >, = and<.
$0\ ......\ \frac{-3}{-5}$
Answer
$0<\frac{-3}{-5}$

Solution:

$\frac{-3}{-5}=\frac{-3\times(-1)}{-5\times(-1)}=\frac{3}{5}$

It is clear that $0<\frac{3}{5}$

$0<\frac{-3}{-5}$

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