MCQ
Binding energy of a certain nucleus is $18 \times 10^8 \mathrm{~J}$. How much is the difference between total mass of all the nucleons and nuclear mass of the given nucleus:
  • A
    $0.2 \mu \mathrm{g}$
  • B
    $20 \mu \mathrm{g}$
  • C
    $2 \mu \mathrm{g}$
  • $10 \mu \mathrm{g}$

Answer

Correct option: D.
$10 \mu \mathrm{g}$
d
$\Delta \mathrm{mc}^2=18 \times 10^8$

$\Delta \mathrm{m} \times 9 \times 10^{16}=18 \times 10^8$

$\Delta \mathrm{m}=2 \times 10^{-8} \mathrm{~kg}=20 \mu \mathrm{g}$

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