MCQ
Binding energy of hydrogen atom is $13.6\, eV .$ The binding energy of a singly ionized helium atom is : ............ $\mathrm{eV}$
- A$13.6$
- B$27.2$
- ✓$54.4$
- D$3.4$
✓
Answer
Correct option: C.
$54.4$
c
$\frac{E_{H e}}{{E_H}}=\frac{\frac{-13.6(2)^2}{n^2}}{\frac{-13.6(1)^2}{n^2}}$
$\frac{E_{H e}}{{E_H}}=\frac{\frac{-13.6(2)^2}{n^2}}{\frac{-13.6(1)^2}{n^2}}$
$E_{H e}=4 \times 13.6\, eV$
$E_{H e}=54.4 \,eV$
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