MCQ
Bond formed in crystal by anion and cation is
- ✓Ionic
- BMetallic
- CCovalent
- DDipole
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$(A)$ The acidity of compound $I$ is due to delocalization in the conjugate base.
$(B)$ The conjugate base of compound IV is aromatic.
$(C)$ Compound II becomes more acidic, when it has a $- NO _2$ substituent.
$(D)$ The acidity of compounds follows the order $I > IV > V > II > III$.

$X$ and $Y$ respectively are :
$H_2C = CH - CH_2 - I \xrightarrow[CC{{l}_{4}}]{HI(excess)}$