MCQ
Bond order of ${O_2}$ is
- ✓$2$
- B$1.5$
- C$3$
- D$3.5$
${O_2} = {(\sigma 1s)^2}{({\sigma ^*}1s)^2}{(\sigma 2s)^2}{({\sigma ^*}2s)^2}{({\sigma ^*}2p_z)^2}$
$(\pi 2p_x^2 \equiv \pi 2p_y^2)\;({\pi ^*}2p_x^1 \equiv {\pi ^*}2p_y^1)$
Hence bond order $ = \frac{1}{2}\left[ {{N_b} - {N_a}} \right]$ $ = \frac{1}{2}[10 - 6] = 2$.
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$(I)$ $C{H_2} = CH\mathop C\limits^ + HC{H_3}$
$\begin{array}{*{20}{c}} {{\mkern 1mu} {\mkern 1mu} {\mkern 1mu} {\mkern 1mu} \,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,C{H_3}} \\ {\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,} \\ {(II)\,\,\,\,\,\,\,\,\,\,C{H_2} = C - \mathop {{\text{ }}C}\limits^ + {H_2}} \end{array}$
$(III)$ $C{H_3}CH = CH\mathop C\limits^ + {H_2}$
$\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{CuO} \rightarrow \mathrm{x\,CO}_{2}+\frac{y}{2} \mathrm{H}_{2} \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_{2}+\left(2\, \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{Cu}$
The value of $y$ is ...... .(Integer answer)
$Z$ is