MCQ
The transformation occurring in Duma's method is given below :

$\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{CuO} \rightarrow \mathrm{x\,CO}_{2}+\frac{y}{2} \mathrm{H}_{2} \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_{2}+\left(2\, \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{Cu}$

The value of $y$ is ...... .(Integer answer)

  • A
    $2$
  • $7$
  • C
    $1$
  • D
    $15$

Answer

Correct option: B.
$7$
b
$\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{CuO} \rightarrow \mathrm{x} \mathrm{CO}_{2}+\frac{\mathrm{y}}{2} \mathrm{H}_{2} \mathrm{O}+\frac{\mathrm{z}}{2} \mathrm{~N}_{2}+\left(2 \mathrm{x}+\frac{\mathrm{y}}{2}\right) \mathrm{Cu}$

On balancing

$\mathrm{C}_{2} \mathrm{H}_{7} \mathrm{~N}+\frac{15}{2} \mathrm{CuO} \rightarrow 2 \mathrm{CO}_{2}+\frac{7}{2} \mathrm{H}_{2} \mathrm{O}+\frac{1}{2} \mathrm{~N}_{2}+\frac{15}{2} \mathrm{Cu}$

On comparing

$\mathrm{y}=7$

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