$\mathop {HSO_4^ - }\limits_{{\rm{base}}} + {H^ + }⇌ {H_2}S{O_4}$
$\mathop {HSO_4^ - }\limits_{{\rm{acid}}} ⇌SO_4^{2 - } + {H^ + }$
(આપેલ : $K _{ b }\left( NH _4 OH \right)=1 \times 10^{-5}, \log 2=0.30, \log 3=0.48, \log 5=0.69, \log 7=0.84, \log 11=$ $1.04)$