Question
By the graphical method, find whether the following pair of equations are consistent or not. If consistent, solve them:
$3x + y + 4 = 0, 6x - 2y + 4 = 0.$

Answer

Given pair of equations is 3x + y + 4 = 0 .....(i) and 6x - 2y + 4 = 0 .....(ii)
on comparing with ax + bc + c = 0,
we get $a_1 = 3, b_1 = 1$ and $c_1 = 4$
[from Eq. (i)] $a_2 = 6, b_2 = -1$ and $c_2 = 4$ [from Eq. (ii)]
Here, $\frac{\text{a}_1}{\text{a}_2}=\frac{3}{6}=\frac{1}{2}$;
$\frac{\text{b}_1}{\text{b}_2}=\frac{1}{-2}$ and $\frac{\text{c}_1}{\text{c}_2}=\frac{4}{4}=\frac{1}{2}$
$\because\ \frac{\text{a}_1}{\text{a}_2}\neq\frac{\text{b}_1}{\text{b}_2}$
So, the given pair of linear equations are intersecting at one point, therefore these lines have unique solution.
Hence, given pair of linear equations is consistent.
We have, 3x + y + 4 = 0 y = -4 - 3x
When x = 4 then y = -4
When x = -1,
then y = -4
When x = 1,
then y = 2
x 0 -1 -2
y -4 -1 2
Points B C A
and 6x - 2y + 4 = 0 ⇒ 2y = 6x + 4 ⇒ y = 3x + 2 When x = 0, then y = 2 When x = -1, then y = -1 When x = 1, then y = 5
x -1 0 1
y -1 2 5
Points C Q p
Plotting the points B(0, -4) and A(-2, 2), we get the straight tine AB. Plotting the points Q(0, 2) and P(1, 5), we get the seraight line PQ. The lines AB and PQ intersect at C (-1, -1).

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