MCQ
C- H bond type in benzene is:
- A$\sigma$ sp−s
- B$\sigma$ sp2−s
- C$\sigma$ sp3−s
- D$\sigma$ p−p
Explanation:
In benzene molecule, six carbon atoms are in sp2 hybridization and hydrogen atoms have pure 's' orbitals. Overlap is sp2−s overlap with formation of a sigma bond.
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| List $I$(Quantum Number) | List $II$(Information provided) |
| $A$. mı | $I$. Shape of orbital |
| $B$. $m_s$ | $II$. Size of orbital |
| $C$. $1$ | $III$. Orientation of orbital |
| $D$. $\mathrm{n}$ | $IV$. Orientation of spin of electron |
Choose the correct answer from the options given below :


$n = 4$______________
$n = 3$______________
$n = 2$ _____________
$n = 1$______________
$4Fe + 3{O_2}\, \to \,4F{e^{3 + }} + 6{O^{2 - }}$
Which one of the following statement is incorrect