${C_2}{H_5}Br\,\xrightarrow{{AgCN}}X\xrightarrow[{Zn - Hg/HCl}]{{{\text{Reduction}}}}Y,$ Here $Y$ is
  • A
    Ethyl methyl amine
  • B$n-$ propylamine
  • C
    Isopropylamine
  • D
    Ethylamine
AIEEE 2012, Difficult
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